Advertisements
Advertisements
प्रश्न
The sum which amounts to ₹ 2662 at 10% p.a in 3 years, compounded yearly is _________
विकल्प
₹ 2000
₹ 1800
₹ 1500
₹ 2500
उत्तर
₹ 2000
Explanation;
Hint:
Amount = ₹ 2662
Rate of interest = 10% p.a
Time period = 3 years ...[Compounded yearly]
Principal (P) → required to find?
Applying formula A = `"P"(1 + "r"/100)^"n"`
2662 = `"P"(1 + 10/100)^3`
= `"P"((100 + 10)/100)^3`
2662 = `"P"(110/100)^3`
2662 = `"P"(11/10)^3`
∴ P = `(2662 xx 10 xx 10 xx 10)/(11 xx 11 xx 11)`
= 2 × 10 × 10 × 10
= ₹ 2000
APPEARS IN
संबंधित प्रश्न
The present population of a town is 28000. If it increases at the rate of 5% per annum, what will be its population after 2 years?
Rachna borrows Rs. 12,000 at 10 percent per annum interest compounded half-yearly. She repays Rs. 4,000 at the end of every six months. Calculate the third payment she has to make at end of 18 months in order to clear the entire loan.
Rekha borrowed Rs. 40,000 for 3 years at 10% per annum compound interest. Calculate the interest paid by her for the second year.
Calculate the compound interest for the second year on Rs. 15000 invested for 5 years at 6% per annum.
Rohit borrowed ₹ 40,000 for 2 years at 10% per annum C.I. and Manish borrowed the same sum for the same time at 10.5% per annum simple interest. Which of these two gets less interest and by how much?
The compound interest payable annually on a certain sum for 2 years is Rs 40.80 and the simple interest is Rs 40. Find the sum and the rate percent.
The compound interest on ₹ 5000 at 12% p.a for 2 years, compounded annually is ___________
Suppose for the principal P, rate R% and time T, the simple interest is S and compound interest is C. Consider the possibilities.
- C > S
- C = S
- C < S
Then
A sum is taken for two years at 16% p.a. If interest is compounded after every three months, the number of times for which interest is charged in 2 years is ______.
To calculate the growth of a bacteria if the rate of growth is known, the formula for calculation of amount in compound interest can be used.
