Question

The surface tension of the two liquids is respectively 20 and 60 dyne cm^-1. The liquids drop from the ends of two tubes of the same radius. The ratio of the weights of the two drops is ______

विकल्प

• 1 : 2

• 1 : 3

• 2 : 3

• 3 : 4

Answer 1

The surface tension of the two liquids is respectively 20 and 60 dyne cm^-1. The liquids drop from the ends of two tubes of the same radius. The ratio of the weights of the two drops is 1 : 3.

Explanation:

Weight = 2πrT

Hence, radius remaining constant, W ∝ T

∴ `"W"_1/"W"_2 = "T"_1/"T"_2 = 20/60 = 1/3`