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प्रश्न
The time taken by 50 students to complete a 100-meter race are given below. Find its standard deviation
Time taken (sec) | 8.5 − 9.5 | 9.5 − 10.5 | 10.5 − 11.5 | 11.5 − 12.5 | 12.5 − 13.5 |
Number of students | 6 | 8 | 17 | 10 | 9 |
उत्तर
Assumed mean = 11
Time taken | Number of students fi |
mid value xi |
di = xi − A = xi − 11 |
fidi | fidi2 |
8.5 − 9.5 | 6 | 9 | − 2 | − 12 | 24 |
9.5 − 10.5 | 8 | 10 | − 1 | − 8 | 8 |
10.5 − 11.5 | 17 | 11 | 0 | 0 | 0 |
11.5 − 12.5 | 10 | 12 | 1 | 10 | 10 |
12.5 − 13.5 | 9 | 13 | 2 | 18 | 36 |
`sumf_"i"` = 50 | `sumf_"i""d"_"i"` = 8 | `sumf_"i""d"_"i"^2` = 78 |
Here N = 50, `sumf_"i""d"_"i"` = 8, `sumf_"i""d"_"i"^2` = 78
Standard deviation (σ) = `sqrt((sumf_"i""d"_"i"^2)/"N" - ((sumf_"i""d"_"i")/"N")^2`
= `sqrt(78/50 - (8/50)^2`
= `sqrt(1.56 - (0.16)^2`
= `sqrt(1.56 - 0.025)`
= `sqrt(1.56 - 0.03)`
= `sqrt(1.53)`
= 1.236
⇒ 1.24
∴ Standard deviation (σ) = 1.24
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