मराठी
तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता १०

The time taken by 50 students to complete a 100-meter race are given below. Find its standard deviation Time taken (sec) 8.5 − 9.5 9.5 − 10.5 10.5 − 11.5 11.5 − 12.5 12.5 − 13.5 - Mathematics

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प्रश्न

The time taken by 50 students to complete a 100-meter race are given below. Find its standard deviation

Time taken (sec) 8.5 − 9.5 9.5 − 10.5 10.5 − 11.5 11.5 − 12.5 12.5 − 13.5
Number of students 6 8 17 10 9
बेरीज

उत्तर

Assumed mean = 11

Time taken Number of students
fi
mid value
xi
di = xi − A
= xi − 11
fidi fidi2
8.5 − 9.5 6 9 − 2 − 12 24
9.5 − 10.5 8 10 − 1 − 8 8
10.5 − 11.5 17 11 0 0 0
11.5 − 12.5 10 12 1 10 10
12.5 − 13.5 9 13 2 18 36
  `sumf_"i"` = 50     `sumf_"i""d"_"i"` = 8 `sumf_"i""d"_"i"^2` = 78

Here N = 50, `sumf_"i""d"_"i"` = 8, `sumf_"i""d"_"i"^2` = 78

Standard deviation (σ) = `sqrt((sumf_"i""d"_"i"^2)/"N" - ((sumf_"i""d"_"i")/"N")^2`

= `sqrt(78/50 - (8/50)^2`

= `sqrt(1.56 - (0.16)^2`

= `sqrt(1.56 - 0.025)`

= `sqrt(1.56 - 0.03)`

= `sqrt(1.53)`

= 1.236

⇒ 1.24

∴ Standard deviation (σ) = 1.24

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Measures of Dispersion
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पाठ 8: Statistics and Probability - Exercise 8.1 [पृष्ठ ३१४]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
पाठ 8 Statistics and Probability
Exercise 8.1 | Q 13 | पृष्ठ ३१४

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