Advertisements
Advertisements
प्रश्न
The two co-initial adjacent sides of a parallelogram are `2hati - 4hatj - 5hatk and 2hati + 2hatj + 3hatk`. Find its diagonals and use them to find the area of the parallelogram.
योग
उत्तर
`overset->d_1 = overset->a + overset->b = 4hati - 2hatj - 2hatk, overset->d_2 = overset->a - overset->b = -6hatj - 8hatk`
Area of the parallelogram = `1/2|overset->d_1 xx overset->d_2|`
= `1/2||(hati, hatj,hatk), (4, -2, -2), (0, -6, -8)||`
= `2|hati + 8hatj -6hatk|`
Area of the parallelogram = `2sqrt101` sq. units.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
