हिंदी

The two waves are represented by Y1 = t10-2sin[50t+x25+0.3]m and Y2 = t10-2cos[50t+x25]m where x is in metre and time in second. The phase difference between the two waves is nearly _________. -

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प्रश्न

The two waves are represented by Y1 = `10-2 sin [50"t" + x/25 + 0.3]`m and Y2 = `10^-2 cos [50"t" + x/25]`m where x is in metre and time in second. The phase difference between the two waves is nearly _________.

विकल्प

  • 1.22 rad

  • 1.05 rad

  • 1.15 rad

  • 1.27 rad

MCQ
रिक्त स्थान भरें

उत्तर

The two waves are represented by Y1 = `10-2 sin [50"t" + x/25 + 0.3]`m and Y2 = `10^-2 cos [50"t" + x/25]`m where x is in metre and time in second. The phase difference between the two waves is nearly 1.27 rad.

Explanation:

Y1 = `10-2 sin [50"t" + x/25 + 0.3]`m

Y2 = `10^-2 cos [50"t" + x/25]`m

∴ Phase difference between the two waves is

`phi = pi/2 - 0.3 = 1.57 - 0.3 = 1.27`rad

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Superposition of Waves
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