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प्रश्न
The two waves are represented by Y1 = `10-2 sin [50"t" + x/25 + 0.3]`m and Y2 = `10^-2 cos [50"t" + x/25]`m where x is in metre and time in second. The phase difference between the two waves is nearly _________.
पर्याय
1.22 rad
1.05 rad
1.15 rad
1.27 rad
MCQ
रिकाम्या जागा भरा
उत्तर
The two waves are represented by Y1 = `10-2 sin [50"t" + x/25 + 0.3]`m and Y2 = `10^-2 cos [50"t" + x/25]`m where x is in metre and time in second. The phase difference between the two waves is nearly 1.27 rad.
Explanation:
Y1 = `10-2 sin [50"t" + x/25 + 0.3]`m
Y2 = `10^-2 cos [50"t" + x/25]`m
∴ Phase difference between the two waves is
`phi = pi/2 - 0.3 = 1.57 - 0.3 = 1.27`rad
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Superposition of Waves
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