Advertisements
Advertisements
प्रश्न
The value of (3x3 + 9x2 + 27x) ÷ 3x is ______.
विकल्प
x2 + 9 + 27x
3x3 + 3x2 + 27x
3x3 + 9x2 + 9
x2 + 3x + 9
उत्तर
The value of (3x3 +9x2 + 27x) ÷ 3x is x2 + 3x + 9.
Explanation:
We have,
`(3x^3 + 9x^2 + 27x) + 3x = (3x^3 + 9x^2 + 27x)/(3x)`
= `(3x^3)/(3x) + (9x^2)/(3x) + (27x)/(3x)`
= x2 + 3x + 9
APPEARS IN
संबंधित प्रश्न
Identify the terms, their coefficients for the following expressions.
5xyz2 − 3zy
For the following monomials, write its degree: – x2y
Write numerical co-efficient of the following: y
In -5x3y2z4 ; write the coefficient of yz2. Also, write the degree of the given algebraic expression.
Fill in the blank:
6x2y + 13xy2 – 4x2y + 2xy2 = _______
Find the sum of: 5x2 – 2xy + 3y2 and – 2x2 + 5xy + 9y2 and 3x2 -xy- 4y2
Find the sum of: 9ax – 6bx + 8, 4ax + 8bx – 7 and – 6ax – 46x – 3
The number of terms in the expression 3ab + 4c – 9 is __________
Write the greatest common factor in the following terms.
3x3y2z, – 6xy3z2, 12x2yz3
Factorise the following expression.
a2b + a2c + ab + ac + b2c + c2b
