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प्रश्न
The vapour pressure of solvent decreases by 1 O mm Hg, if mole fraction of non-volatile solute is 0.2. Calculate vapour pressure of solvent.
विकल्प
70 mm of Hg
40 mm of Hg
50 mm of Hg
60 mm of Hg
MCQ
उत्तर
50 mm of Hg
Explanation:
Given, Lowering of vapour pressure
`("p"_4^circ - "p"_"A")` = 10 mm Hg
Mole fraction of non-volatile solution (χA) = 0.2
Mole fraction of solution,
`chi_"A" = ("p"_4^circ - "p"_"A")/"p"_"A"`
`0.2 = (100 "mm" "Hg")/"p"_"A"`
`=> "p"_"A" = 10/0.2`mm Hg = 50 mm of Hg
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Vapour Pressure Lowering
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