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Question
The vapour pressure of solvent decreases by 1 O mm Hg, if mole fraction of non-volatile solute is 0.2. Calculate vapour pressure of solvent.
Options
70 mm of Hg
40 mm of Hg
50 mm of Hg
60 mm of Hg
MCQ
Solution
50 mm of Hg
Explanation:
Given, Lowering of vapour pressure
`("p"_4^circ - "p"_"A")` = 10 mm Hg
Mole fraction of non-volatile solution (χA) = 0.2
Mole fraction of solution,
`chi_"A" = ("p"_4^circ - "p"_"A")/"p"_"A"`
`0.2 = (100 "mm" "Hg")/"p"_"A"`
`=> "p"_"A" = 10/0.2`mm Hg = 50 mm of Hg
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Vapour Pressure Lowering
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