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प्रश्न
The velocity-time plot for a particle moving on a straight line is shown in the figure.
(a) The particle has a constant acceleration.
(b) The particle has never turned around.
(c) The particle has zero displacement.
(d) The average speed in the interval 0 to 10 s is the same as the average speed in the interval 10 s to 20 s.
उत्तर
(a) The particle has a constant acceleration.
(d) The average speed in the interval 0 s to 10 s is the same as the average speed in the interval 10 s to 20 s.
Explanation:
(a) The slope of the v–t graph gives the acceleration. For the given graph, the slope is constant. So, acceleration is constant.
(b) From 0 to 10 seconds, velocity is in positive direction and then in negative direction. This means that the particle turns around at t = 10 s.
(c) Area in the v–t curve gives the distance travelled by the particle.
Distance travelled in positive direction \[\neq\] Distance travelled in negative direction
∴ Displacement \[\neq\] Zero
(d) The area of the v–t graph from t = 0 s to t = 10 s is the same as that from t = 10 s to t= 20 s. So, the distance covered is the same. Hence, the average speed is the same.
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