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Three cells, each of emf E but internal resistances 2r, 3r and 6r are connected in parallel across a resistor R. Obtain expressions for (i) current flowing in the circuit, and (ii) the terminal - Physics

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प्रश्न

Three cells, each of emf E but internal resistances 2r, 3r and 6r are connected in parallel across a resistor R.

Obtain expressions for (i) current flowing in the circuit, and (ii) the terminal potential differences across the equivalent cell.

व्युत्पत्ति

उत्तर

`R_{AB}` = ?

`1/(R_{AB}) = 1/(2r) + 1/(3r) + 1/(6r)`

`1/R_{AB} = 1/r[(3 + 2 + 1)/6]`

`1/R_{AB} = 1/r`

`R_{AB} = r` ⇒ equivalent internal resistant

Equivalent emf of cells in parallel,

`E_{eq} = (E_1/r_1 + E_2/r_2 + E_3/r_3)/(1/r_1 + 1/r_2 + 1/r_3)`

= `(E/(2r) + E/(3r) + E/(6r))/(1/(2r) + 1/(3r) + 1/(6r))`

`E_{eq} = E[(1/(2r) + 1/(3r) + 1/(6r))/(1/(2r) + 1/(3r) + 1/(6r))]`

Eeq = E

Current flowing in the circuit,

I = `E_{eq}/(R + R_{AB})`

I = `E/(R + r)`

Potential drop across E,

V = IReq

V = `(rE)/(R + r)`

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2022-2023 (March) Delhi Set 1

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