Advertisements
Advertisements
प्रश्न
Three strings of lengths 50 m 75 cm; 68 m 58 cm and 121 m 3 cm, respectively, are joined together to get a single string of greatest length, And the length of the single string obtained.
If this single string is then divided into 12 equal pieces; find the length of each piece.
उत्तर
1st string 50 m 75 cm = 50.75 m
2nd string 68 m 58 cm = 68.58 m
3rd string 121 m 3 cm= 121.03 m
On joining three total length = 240.36 m
Now, one string = 240.36 m
Dividing 12 parts = `240.36/12` = 20.3 m.
APPEARS IN
संबंधित प्रश्न
What least number must be added to 89.376 to get 1000?
Subtract:
Rs. 35.74 from Rs. 63.22
Add (giving the answer in metre):
0.93 m and 64 cm
Add (giving the answer in kg):
2.06 kg and 57.864 kg
83 note-books are sold at Rs. 15.25 each. Find the total money (in rupees) obtained by selling these note-books.
If the length of one bed-cover is 2.1 m, find the total length of 17 bed-covers.
A piece of rope is 10 m 67 cm long. Another rope is 16 m 32 cm long. By how much is the second rope longer than the first one?
A car can run 16.8 km consuming one litre of petrol. How many kilometres will it run on 3.7 litres of petrol?
A certain amount of money is distributed among 28 persons. If each person gets Rs. 62.45 and Rs. 5.78 is left, find the original amount of money
Complete the following table:
Item | Cost per kg | Quantity | Amount | |
(i) | A | Rs. 17.40 | 2.5 kg | ............... |
(ii) | B | Rs. 42.25 | 1.6 kg | .............. |
(iii) | C | Rs. 28.50 | 3.2 kg | .............. |
Total = | ................ |