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Three Strings of Lengths 50 M 75 Cm; 68 M 58 Cm and 121 M 3 Cm, Respectively, Are Joined Together to Get a Single String of Greatest Length, and the Length of the Single String Obtained. - Mathematics

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Question

Three strings of lengths 50 m 75 cm; 68 m 58 cm and 121 m 3 cm, respectively, are joined together to get a single string of greatest length, And the length of the single string obtained.
If this single string is then divided into 12 equal pieces; find the length of each piece.

Sum

Solution

1st string 50 m 75 cm = 50.75 m
2nd string 68 m 58 cm = 68.58 m
3rd string 121 m 3 cm= 121.03 m
On joining three total length = 240.36 m
Now, one string = 240.36 m
Dividing 12 parts = `240.36/12` = 20.3 m.

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Word Problems Involving Addition and Subtraction of Decimals (Two Operations Together on Money, Mass, Length and Temperature).
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Chapter 15: Decimal Fractions - Exercise 15 (E)

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Selina Mathematics [English] Class 6
Chapter 15 Decimal Fractions
Exercise 15 (E) | Q 10
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