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Two groups are competing for the position on the board of directors of a corporation. The probabilities that the first and the second groups will win are 0.6 and 0.4 respectively. - Mathematics

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प्रश्न

Two groups are competing for the position on the board of directors of a corporation. The probabilities that the first and the second groups will win are 0.6 and 0.4 respectively. Further, if the first group wins, the probability of introducing a new product is 0.7 and the corresponding probability is 0.3 if the second group wins. Find the probability that the new product introduced was by the second group.

योग

उत्तर

Let E1: 'First group wins' and E2: 'Second group wins'

⇒  `P (E_1) = 0.6 = 6/10`

and `P (E_2) = 0.4 = 4/10`

Let A: 'New product is introduced`

Then `P (A|E_1) = 0.7 = 7/10`

and `P (A|E_2) = 0.3 = 3/10`

Hence the required probability is

`= P (E_2 |A) = (P(A|E_2) P (E_2))/(P (A|E_1) P (E_1) + P (A| E_2) P (E_2))`

`= (3/10 xx 4/10)/(7/10 xx 6/10 + 3/10 xx 4/10)`

`= 12/(42 + 12)`

`= 12/54`

`= 2/9`

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अध्याय 13: Probability - Exercise 13.3 [पृष्ठ ५५६]

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एनसीईआरटी Mathematics [English] Class 12
अध्याय 13 Probability
Exercise 13.3 | Q 9 | पृष्ठ ५५६

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