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प्रश्न
Two-point charges placed in a medium of dielectric constant 5 are at a distance r between them, experience an electrostatic force ‘F’. The electrostatic force between them in vacuum at the same distance r will be ____________.
विकल्प
5F
F
F/2
F/5
MCQ
रिक्त स्थान भरें
उत्तर
Two-point charges placed in a medium of dielectric constant 5 are at a distance r between them, experience an electrostatic force ‘F’. The electrostatic force between them in a vacuum at the same distance r will be 5F.
Explanation:
`("Q"_1 "Q"_2)/"r" "k" = 5` `"F" = 1/(4 piepsilon"ok") ("Q"_1 "Q"_2)/"r"^2`
`("Q"_1 "Q"_2)/"r"` Force in the charges in the air is
`"F"^- = 1/(4piepsilon"o") ("Q"_1 "Q"_2)/"r"^2`
k = F
= 5 F
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