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Two-point charges placed in a medium of dielectric constant 5 are at a distance r between them, experience an electrostatic force ‘F’. The electrostatic force between them in vacuum -

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Question

Two-point charges placed in a medium of dielectric constant 5 are at a distance r between them, experience an electrostatic force ‘F’. The electrostatic force between them in vacuum at the same distance r will be ____________.

Options

  • 5F

  • F

  • F/2

  • F/5

MCQ
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Solution

Two-point charges placed in a medium of dielectric constant 5 are at a distance r between them, experience an electrostatic force ‘F’. The electrostatic force between them in a vacuum at the same distance r will be 5F.

Explanation:

`("Q"_1                 "Q"_2)/"r"  "k" = 5`            `"F" = 1/(4 piepsilon"ok") ("Q"_1 "Q"_2)/"r"^2`

`("Q"_1                 "Q"_2)/"r"`  Force in the charges in the air is

`"F"^- = 1/(4piepsilon"o") ("Q"_1 "Q"_2)/"r"^2`

k = F

= 5 F

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