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Use the periodic table to answer the following question. Identify an element that would tend to lose two electrons. - Chemistry

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प्रश्न

Use the periodic table to answer the following question.

Identify an element that would tend to lose two electrons.

संक्षेप में उत्तर

उत्तर १

An element having two valence electrons will lose two electrons easily to attain the stable noble gas configuration. The general electronic configuration of such an element will be ns2. This is the electronic configuration of group 2 elements. The elements present in group 2 are Be, Mg, Ca, Sr, Ba.

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उत्तर २

Element belonging to alkaline earth family (group 2) e.g., magnesium

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अध्याय 3: Classification of Elements and Periodicity in Properties - EXERCISES [पृष्ठ ९७]

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एनसीईआरटी Chemistry - Part 1 and 2 [English] Class 11
अध्याय 3 Classification of Elements and Periodicity in Properties
EXERCISES | Q 3.27 - (b) | पृष्ठ ९७

संबंधित प्रश्न

Write the atomic number of the element present in the third period and a seventeenth group of the periodic table.


Use the periodic table to answer the following question.

Identify an element with five electrons in the outer subshell.


Use the periodic table to answer the following question.

Identify an element that would tend to gain two electrons.


Use the periodic table to answer the following question.

Identify the group having metal, non-metal, liquid as well as gas at room temperature.


Assign the position of the element having an outer electronic configuration in the periodic table.

(n - 2) f7 (n - 1)d1 ns2 for n = 6


Write the outer electronic configuration of the following using the orbital notation method. Justify.

Po (belongs to period 6 and group 16)


Write the outer electronic configuration of the following using the orbital notation method. Justify.

Cu (belongs to period 4 and group 11)


Answer the following question.

The electronic configuration of some element is given below:

1s2

In which group and period of the periodic table the element is placed?


Answer the following question.

For s-block and p-block elements show that the number of valence electrons is equal to its group number.


Consider the oxides Li2O, CO2, B2O3.

Which oxide would you expect to be the most basic?


Consider the oxides Li2O, CO2, B2O3.

Give the formula of an amphoteric oxide.


The first ionisation enthalpies of \[\ce{Na, Mg, Al}\] and \[\ce{Si}\] are in the order:


In the modern periodic table, elements are arranged in order of increasing atomic numbers which is related to the electronic configuration. Depending upon the type of orbitals receiving the last electron, the elements in the periodic table have been divided into four blocks, viz, s, p, d and f. The modern periodic table consists of 7 periods and 18 groups. Each period begins with the filling of a new energy shell. In accordance with the Arfbau principle, the seven periods have 2, 8, 8, 18, 18, 32 and 32 elements respectively. The seventh period is still incomplete. To avoid the periodic table being too long, the two series of f-block elements, called lanthanoids and actinoids are placed at the bottom of the main body of the periodic table.

The electronic configuration of the element which is just above the element with atomic number 43 in the same group is ______.


Which of the following sets contain only isoelectronic ions?

(i) \[\ce{Zn^{2+}, Ca^{2+}, Ga^{3+}, Al^{3+}}\]

(ii) \[\ce{K+ , Ca^{2+}, Sc^{3+}, Cl-}\]

(iii) \[\ce{P^{3-}, S^{2-}, Cl- , K+}\]

(iv) \[\ce{Ti^{4+}, Ar, Cr^{3+}, V^{5+}}\]


Identify the group and valency of the element having atomic number 119. Also predict the outermost electronic configuration and write the general formula of its oxide.


Write down the outermost electronic configuration of alkali metals. How will you justify their placement in group 1 of the periodic table?


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