हिंदी

Using the figures given below, frame problems based on profit percent or loss percent.​ ​Cost price ₹ 8600, transport charges ₹ 250, porterage ₹ 150, selling price ₹ 10000 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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प्रश्न

Using the figures given below, frame problems based on profit percent or loss percent.

​Cost price ₹ 8600, transport charges ₹ 250, porterage ₹ 150, selling price ₹ 10000

योग

उत्तर

Problem: Vinay bought a machine from a factory for Rs 8600. He spent Rs 250 on transport and Rs 150 on porterage. If he sold it to a customer for Rs 10000, what was his profit percent or loss percent?

Cost price of machine = ₹ 8600

Money spent on transport = ₹ 250

Money spent on porterage = ₹ 150

Total expenses = cost of machine + transport charges + porterage charges

= 8600 + 250 + 150

= ₹ 9000

That is, total cost price = ₹ 9000

Selling price of the machine = ₹ 10000

Since selling price is more than total cost price, so there is a profit.

Profit = Selling price − total cost price

= 10000 − 9000

= ₹ 1000

Let x % be the Vinay's profit in this transaction. Then,

x100=Profittotal cost price=10009000

x100×100=10009000×100

x=1009=1119

∴ Vinay made a profit of 1119% in this transaction.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Profit – Loss - Practice Set 34 [पृष्ठ ७२]

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बालभारती Mathematics [English] 6 Standard Maharashtra State Board
अध्याय 13 Profit – Loss
Practice Set 34 | Q 5 | पृष्ठ ७२
बालभारती Integrated 6 Standard Part 3 [English Medium] Maharashtra State Board
अध्याय 3.4 Profit-Loss
Practice Set 34 | Q 5. | पृष्ठ ६७

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