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प्रश्न
Using the following data, draw time - displacement graph for a moving object:
| Time (s) | 0 | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 |
| Displacement (m) | 0 | 2 | 4 | 4 | 4 | 6 | 4 | 2 | 0 |
Use this graph to find average velocity for the first 4 s, for the next 4 s and for the last 6 s.
उत्तर
From the given data, the displacement-time graph is shown as
Average velocity = `("Change in displacement")/("time interval")`
∴ For first 4s, v1 = `(4 - 0)/4`
= 1 ms−1
For next 4s v2 = `(4 - 4)/4`
= 0 ms−1
For last 6s v3 = `(0 - 6)/6`
= −1 ms−1
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| Time (s) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Distance travelled by A (m) | 0 | 20 | 80 | 180 | 240 | 300 | 360 | 420 |
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| 1. | Displacement | Knot |
| 2. | Light travelling through vacuum | Geometric centre |
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| 4. | Centre of gravity of geometrical shaped objects | Larger base area |
| 5. | Stability | Uniform velocity |
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