Advertisements
Advertisements
प्रश्न
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(1 + 3b)(3b – 1)
उत्तर
(1 + 3b)(3b – 1)
(1 + 3b)(3b – 1) can be written as (3b + 1)(3b – 1)
Substituting a = 3b and b = 1
In (a + b)(a – b) = a2 – b2, we get
(3b + 1)(3b – 1) = (3b)2 – 12
= 32 × b2 – 12
(3b + 1)(3b – 1) = 9b2 – 12
APPEARS IN
संबंधित प्रश्न
Find the value of (x – y)(x + y)(x2 + y2)
Simplify (5x – 3y)2 – (5x + 3y)2
672 – 372 = (67 – 37) × ______ = ______.
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(2p^2)/25 - 32q^2`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(x^3y)/9 - (xy^3)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`1/36a^2b^2 - 16/49b^2c^2`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 81
Factorise the expression and divide them as directed:
(2x3 – 12x2 + 16x) ÷ (x – 2)(x – 4)
The radius of a circle is 7ab – 7bc – 14ac. Find the circumference of the circle. `(pi = 22/7)`
Verify the following:
`((3p)/7 + 7/(6p))^2 - (3/7p + 7/(6p))^2 = 2`
