Question

Van't Hoff factor (i) for centimolal solution of \[\ce{K3[Fe(CN)6]}\] is 3.333. What is its percentage dissociation?

विकल्प

• 70%

• 33.33%

• 80%

• 77.7%

Answer 1

77.7%

Explanation:

\[\ce{K3[Fe(CN)6] <=> 3K^+  + [Fe(CN)6]^{3-}}\]    ∴ n = 4

`alpha = ("i" - 1)/("n" - 1) = (3.333 - 1)/(4 - 1) = 2.33/3` = 0.7766

∴ % dissociation = 0.7766 × 100 = 77.66%