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Question
Van't Hoff factor (i) for centimolal solution of \[\ce{K3[Fe(CN)6]}\] is 3.333. What is its percentage dissociation?
Options
70%
33.33%
80%
77.7%
MCQ
Solution
77.7%
Explanation:
\[\ce{K3[Fe(CN)6] <=> 3K^+ + [Fe(CN)6]^{3-}}\] ∴ n = 4
`alpha = ("i" - 1)/("n" - 1) = (3.333 - 1)/(4 - 1) = 2.33/3` = 0.7766
∴ % dissociation = 0.7766 × 100 = 77.66%
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Colligative Properties of Electrolytes
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