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Verify whether the following sequence is G.P. If so, find tn. 5,15,155,1255,... - Mathematics and Statistics

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प्रश्न

Verify whether the following sequence is G.P. If so, find tn.

`sqrt(5), 1/sqrt(5), 1/(5sqrt(5)), 1/(25sqrt(5)), ...`

योग

उत्तर

`sqrt(5), 1/sqrt(5), 1/(5sqrt(5)), 1/(25sqrt(5)), ...`

t1 = `sqrt(5)`, t2 = `1/sqrt(5)`, t3 = `1/(5sqrt(5))`, t4 = `1/(25sqrt(5)`, ...

Here, `"t"_2/"t"_1 = "t"_3/"t"_2 = "t"_4/"t"_3 = 1/5`

Since, the ratio of any two consecutive terms is a constant, the given sequence is a geometric progression.

Here, a = `sqrt(5)`, r = `1/5`

tn = arn–1

∴ tn = `sqrt(5) (1/5)^("n" - 1)`

= `(5)^(1/2) (5)^(1 - "n")`

= `(5)^(3/2 - "n")`

shaalaa.com
Sequence and Series - Geometric Progression (G.P.)
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Sequences and Series - EXERCISE 4.1 [पृष्ठ ५०]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] 11 Standard Maharashtra State Board
अध्याय 4 Sequences and Series
EXERCISE 4.1 | Q 1) iii) | पृष्ठ ५०
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