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प्रश्न
What is the effect of catalyst on activation energy of a reaction?
उत्तर
The catalyst provides an alternate pathway or reaction mechanism by reducing the activation energy between reactants and products.
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संबंधित प्रश्न
With the help of the equation ΔG° = - nFEocell. Explain that cell potential is an intensive property.
Write any ‘two’ advantages of calomel electrode.
Potential of saturated calomel electrode is-
What is the effect of catalyst on: Gibbs energy (∆G)
For the reaction
`2AgCl (s) + H_2 (g) ("1 atm") -> 2Ag (s) + 2H^(+) (0.1 M) + 2Cl^(-) (0.1 M)`
`triangleG^0 = -43600 J at 25^@ C`
Calculate the e.m.f. of the cell
`[log 10^(-n) = -n]`
The Gibb's energy change (in J) for the given reaction at [Cu2+] = [Sn2+] = 1 M and 298 K is ______.
\[\ce{Cu(s) + Sn^{2+}(aq) -> Cu^{2+}(aq) + Sn(s)}\]
`["E"_("Sn"^(2+)//"Sn")^0 = -0.16 "V", "E"_("Cu"^(2+)//"Cu")^0 = 0.34 "V", "Take F" = 96500 "C mol"^-1]`
The equilibrium constant at 25°C for the given cell is:
Zn | Zn2+ (1M) | | Ag+ (1M) |
Ag is ______ × 1052.
Given that
\[\ce{E^0_{Zn/Zn^{2+}}}\] = 0.76 V
and \[\ce{E^0_{Ag/Ag^{+}}}\] = −0.80 V
The e.m.f. of cell Zn | ZnSO4 | | CuSO4 | Cu at 25°C is 0.03 V and the temperature coefficient of e.m.f. is −1.4 × 10−4 V/K. The heat of reaction for the change taking place inside the cell is ______ kJ/mol.
The cell potential for the following cell
\[\ce{Pt|H2 (g)| H+ (aq)||Cu^{2+} (0.01 M)| Cu(s)}\]
is 0.576 Vat 298 K. The pH of the solution is ____. (Nearest integer)
The standard Gibbs energy for the given cell reaction in kJ mol-1 at 2'98 K is:
\[\ce{Zn(s) + Cu^{2+} (aq) -> Zn^{2+} (aq) + Cu(s)}\]
E° = 2 V at 298 K
(Faraday's constant, F = 96000 C mol-1)
