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What is the equilibrium constant Keq for the following reaction at 400 K? 2NOClX(g)↽−−⇀2NOX(g)+ClX2X(g), given that H° = 77.2 kJ mol−1 and ∆S° = 122 JK−1 mol−1 - Chemistry

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प्रश्न

What is the equilibrium constant Keq for the following reaction at 400 K?

\[\ce{2NOCl_{(g)} ⇌ 2NO_{(g)} + Cl2_{(g)}}\], given that H0 = 77.2 kJ mol−1 and ∆S0 = 122 JK1 mol1

संख्यात्मक

उत्तर

T = 400 K; ∆H0 = 77.2 kJ mol1 = 77200 J mol1;

∆S0 = 122 JK1 mol1
∆G0 = −2.303 RT log Keq

log Keq = `(-∆"G"^0)/(2.303  "RT")`

log Keq = `((-∆"H"^0 - "T"∆"S"^0))/(2.303  "RT")`

log Keq = `-((77200 - 400  xx 122)/(2.303 xx 8.314 xx 400))`

log Keq = `-((28400)/7659)`

log Keq = − 3.7080

Keq = antilog (−3.7080)

Keq = 1.95 × 10−4

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Gibbs Free Energy (G)
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अध्याय 7: Thermodynamics - Evaluation [पृष्ठ २२६]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 7 Thermodynamics
Evaluation | Q II. 36. | पृष्ठ २२६
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