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Chapters
2: Quantum Mechanical Model of Atom
3: Periodic Classification Of Elements
4: Hydrogen
5: Alkali and Alkaline Earth Metals
6: Gaseous State
▶ 7: Thermodynamics
8: Physical and Chemical Equilibrium
9: Solutions
10: Chemical bonding
11: Fundamentals of Organic Chemistry
12: Basic concept of organic reactions
13: Hydrocarbons
14: Haloalkanes and Haloarenes
15: Environmental Chemistry
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Solutions for Chapter 7: Thermodynamics
Below listed, you can find solutions for Chapter 7 of Tamil Nadu Board of Secondary Education Samacheer Kalvi for Chemistry - Volume 1 and 2 [English] Class 11 TN Board.
Samacheer Kalvi solutions for Chemistry - Volume 1 and 2 [English] Class 11 TN Board 7 Thermodynamics Evaluation [Pages 221 - 227]
Choose the best answer
The amount of heat exchanged with the surrounding at constant pressure is given by the quantity
∆E
∆H
∆S
∆G
All the naturally occurring processes proceed spontaneously in a direction which leads to
decrease in entropy
increase in enthalpy
increase in free energy
decrease in free energy
In an adiabatic process, which of the following is true?
q = w
q = 0
∆E = q
P ∆ V = 0
In a reversible process, the change in entropy of the universe is
> 0
≥ 0
< 0
= 0
In an adiabatic expansion of an ideal gas
w = – ∆u
w = ∆u + ∆H
∆u = 0
w = 0
The intensive property among the quantities below is
mass
volume
enthalpy
`"mass"/"volume"`
An ideal gas expands from the volume of 1 × 10–3 m3 to 1 × 10–2 m3 at 300 K against a constant pressure at 1 × 105 Nm–2. The work done is
– 900 J
900 kJ
270 kJ
– 900 kJ
Heat of combustion is always ___________.
positive
negative
zero
either positive or negative
The heat of formation of CO and CO2 are – 26.4 kCal and – 94 kCal, respectively. Heat of combustion of carbon monoxide will be
+ 26.4 kcal
– 67.6 kcal
– 120.6 kcal
+ 52.8 kcal
C(diamond) → C(graphite), ∆H = –ve, this indicates that
graphite is more stable than diamond
graphite has more energy than diamond
both are equally stable
stability cannot be predicted
The enthalpies of the formation of Al2O3 and Cr2O3 are – 1596 kJ and – 1134 kJ, respectively. ∆H for the reaction \[\ce{2Al + Cr2O3 -> 2Cr + Al2O3}\] is
– 1365 kJ
2730 kJ
– 2730 kJ
– 462 kJ
Which of the following is not a thermodynamic function?
internal energy
enthalpy
entropy
frictional energy
If one mole of ammonia and one mole of hydrogen chloride are mixed in a closed container to form ammonium chloride gas, then
∆H > ∆U
∆H − ∆U = 0
∆H + ∆U = 0
∆H < ∆U
Change in internal energy, when 4 kJ of work is done on the system and 1 kJ of heat is given out by the system is
+ 1 kJ
– 5 kJ
+ 3 kJ
– 3 kJ
The work done by the liberated gas when 55.85 g of iron (molar mass 55.85 g mol–1) reacts with hydrochloric acid in an open beaker at 25°C
– 2.48 kJ
– 2.22 k
+ 2.22 kJ
+ 2.48 kJ
The value of ∆H for cooling 2 moles of an ideal monatomic gas from 125°C to 25°C at constant pressure will be `["given C"_"P" = 5/2"R"]`
– 250 R
– 500 R
500 R
+ 250 R
Given that \[\ce{C_{(g)} + O2_{(g)} -> CO2_{(g)}}\] ∆H° = – a kJ; \[\ce{2CO_{(g)} + O2_{(g)} -> 2CO2_{(g)}}\] ∆H° = – b kJ; Calculate the ∆H° for the reaction \[\ce{C_{(g)} + 1/2O2_{(g)} -> CO_{(g)}}\]
`("b" + 2"a")/2`
2 − b
`(2"a" - "b")/2`
`("b" - 2"a")/2`
When 15.68 litres of a gas mixture of methane and propane are fully combusted at 0°C and 1 atmosphere, 32 litres of oxygen at the same temperature and pressure are consumed. The amount of heat released from this combustion in kJ is (∆HC(CH4) = – 890 kJ mol−1 and ∆HC(C3H8) = – 2220 kJ mol−1)
– 889 kJ
– 1390 kJ
– 3180 kJ
– 632.68 kJ
The bond dissociation energy of methane and ethane are 360 kJ mol–1 and 620 kJ mol–1 respectively. Then, the bond dissociation energy of the C-C bond is
170 kJ mol–1
50 kJ mol–1
80 kJ mol–1
220 kJ mol–1
The correct thermodynamic conditions for the spontaneous reaction at all temperature is
∆H < 0 and ∆S > 0
∆H < 0 and ∆S < 0
∆H > 0 and ∆S = 0
∆H > 0 and ∆S > 0
The temperature of the system, decreases in an ___________.
Isothermal expansion
Isothermal Compression
adiabatic expansion
adiabatic compression
In an isothermal reversible compression of an ideal gas the sign of q, ∆S and w are respectively
+, –, –
–, +, –
+, –, +
–, –, +
Molar heat of vapourisation of a liquid is 4.8 kJ mol–1. If the entropy change is 16 J mol–1 K–1, the boiling point of the liquid is
323 K
27°C
164 K
0.3 K
∆S is expected to be maximum for the reaction
\[\ce{Ca_{(S)} + 1/2O2_{(g)} -> CaO_{(S)}}\]
\[\ce{C_{(S)} + O2_{(g)} -> CO2_{(g)}}\]
\[\ce{N2_{(g)} + O2_{(g)} -> 2NO_{(g)}}\]
\[\ce{CaCO3_{(S)} -> CaO_{(S)} + CO2_{(g)}}\]
The values of ∆H and ∆S for a reaction are respectively 30 kJ mol–1 and 100 JK–1 mol–1. Then the temperature above which the reaction will become spontaneous is
300 K
30 K
100 K
20°C
Write brief answer to the following questions
Answer the following in one or two sentences.
State the first law of thermodynamics.
Define Hess's law of constant heat summation.
Explain intensive properties with two examples.
Define the following term:
Isothermal process
Define the following term:
Adiabatic process
Define the following term:
Isobaric process
Define the following term:
Isochoric process
What is the usual definition of entropy?
What is the unit of entropy?
Predict the feasibility of a reaction when both ΔH and ΔS positive.
Predict the feasibility of a reaction when both ΔH and ΔS negative.
Predict the feasibility of a reaction when ΔH decreases but ΔS increases.
Define is Gibb’s free energy.
Define enthalpy of combustion.
Define molar heat capacity.
Write the unit of molar heat capacity.
Define the calorific value of food.
What is the unit of calorific value?
Define enthalpy of neutralization.
What is lattice energy?
What are state and path functions? Give two examples.
Give Kelvin a statement of the second law of thermodynamics.
The equilibrium constant of a reaction is 10, what will be the sign of ∆G? Will this reaction be spontaneous?
Enthalpy of neutralization is always a constant when a strong acid is neutralized by a strong base: account for the statement.
State the third law of thermodynamics.
Write down the Born-Haber cycle for the formation of CaCl2
Identify the state and path functions out of the following:
- Enthalpy
- Entropy
- Heat
- Temperature
- Work
- Free energy
State the various statements of the second law of thermodynamics.
What are spontaneous reactions?
What are the conditions for the spontaneity of a process?
List the characteristics of internal energy.
Explain how heat absorbed at constant volume is measured using a bomb calorimeter with a neat diagram.
Calculate the work involved in the expansion and compression process.
Derive the relation between ∆H and ∆U for an ideal gas. Explain each term involved in the equation.
Suggest and explain an indirect method to calculate lattice enthalpy of sodium chloride crystal.
List the characteristics of Gibbs free energy.
Calculate the work done when 2 moles of an ideal gas expands reversibly and isothermally from a volume of 500 ml to a volume of 2 L at 25°C and normal pressure.
In a constant volume calorimeter, 3.5 g of gas with molecular weight 28 was burnt in excess oxygen at 298 K. The temperature of the calorimeter was found to increase from 298 K to 298.45 K due to the combustion process. Given that the calorimeter constant is 2.5 kJ K−1. Calculate the enthalpy of combustion of the gas in kJ mol−1.
Calculate the entropy change in the system, and surroundings, and the total entropy change in the universe during a process in which 245 J of heat flows out of the system at 77°C to the surrounding at 33°C.
1 mole of an ideal gas, maintained at 4.1 atm and at a certain temperature, absorbs heat 3710 J and expands to 2 litres. Calculate the entropy change in the expansion process.
30.4 kJ is required to melt one mole of sodium chloride. The entropy change during melting is 28.4 JK−1 mol−1. Calculate the melting point of sodium chloride.
Calculate the standard heat of formation of propane, if its heat of combustion is −2220.2 kJ mol−1 the heats of formation of \[\ce{CO2_{(g)}}\] and \[\ce{H2O_{(l)}}\] are −393.5 and −285.8 kJ mol−1 respectively.
You are given normal boiling points and standard enthalpies of vapourisation. Calculate the entropy of vapourisation of liquids listed below.
Liquid | Boiling points (°C) | ΔH (kJ mol−1) |
Ethanol | 78.4 | + 42.4 |
You are given normal boiling points and standard enthalpies of vapourisation. Calculate the entropy of vapourisation of liquids listed below.
Liquid | Boiling points (°C) | ΔH (kJ mol−1) |
Toluene | 110.6 | + 35.2 |
For the reaction \[\ce{Ag2O_{(s)} -> 2Ag_{(s)} + 1/2O2_{(g)}}\]: ΔH = 30.56 kJ mol−1 and ΔS = 6.66 JK−1 mol−1 (at 1 atm). Calculate the temperature at which ΔG is equal to zero. Also predict the direction of the reaction
- at this temperature and
- below this temperature.
What is the equilibrium constant Keq for the following reaction at 400 K?
\[\ce{2NOCl_{(g)} ⇌ 2NO_{(g)} + Cl2_{(g)}}\], given that H0 = 77.2 kJ mol−1 and ∆S0 = 122 JK−1 mol−1
Cyanamide (NH2CN) is completely burnt in excess oxygen in a bomb calorimeter, ΔU was found to be −742.4 kJ mol−1, calculate the enthalpy change of the reaction at 298 K.\[\ce{NH2CN_{(s)} + 3/2 O2_{(g)} -> N2_{(g)} + CO2_{(g)} + H2O_{(l)}}\] ΔH = ?
Calculate the enthalpy of hydrogenation of ethylene from the following data.
Bond energies of C − H, C − C, C = C and H − H are 414, 347, 618 and 435 kJ mol−1.
Calculate the lattice energy of CaCl2 from the given data
\[\ce{Ca_{(s)} + Cl2_{(g)} -> CaCl2_{(s)}}\] ∆`"H"_"f"^0` = − 795 kJ mol−1
Sublimation: \[\ce{Ca_{(s)} -> Ca-{(g)}}\] ∆`"H"_1^0` = + 121 kJ mol−1
Ionisation: \[\ce{Ca_{(g)} -> Ca^2+_{(g)} + 2e^-}\] ∆`"H"_2^0` = + 2422 kJ mol−1
Dissociation: \[\ce{Cl2_{(g)} -> 2Cl_{(g)}}\] ∆`"H"_3^0` = + 242.8 kJ mol−1
Electron affinity: \[\ce{Cl_{(g)} + e^- -> Cl^-_{(g)}}\] ∆`"H"_4^0` = −355 kJ mol−1
Calculate the enthalpy change for the reaction \[\ce{Fe2O3 + 3CO -> 2Fe + 3CO2}\] from the following data.
\[\ce{2Fe + 3/2O2 -> Fe2O3}\]; ΔH = −741 kJ
\[\ce{C + 1/2O2 -> CO}\]; ΔH = −137 kJ
\[\ce{C + O2-> CO2}\]; ΔH = −394.5 kJ
When 1-pentyne (A) is treated with 4N alcoholic KOH at 175°C, it is converted slowly into an equilibrium mixture of 1.3% 1-pentyne (A), 95.2% 2-pentyne (B) and 3.5% of 1, 2 pentadiene (C) the equilibrium was maintained at 175°C, calculate ΔG0 for the following equilibria.
\[\ce{B ⇌ A}\] `Δ"G"_1^0` = ?
\[\ce{B ⇌ C}\] `Δ"G"_2^0` = ?
At 33K, N2O4 is fifty percent dissociated. Calculate the standard free energy change at this temperature and at one atmosphere.
The standard enthalpies of formation of SO2 and SO3 are −297 kJ mol−1 and −396 kJ mol−1 respectively. Calculate the standard enthalpy of reaction for the reaction: \[\ce{SO2 + 1/2O2 -> SO3}\]
For the reaction at 298 K: \[\ce{2A + B -> C}\]
ΔH = 400 KJ mol−1; ΔS = 0.2 KJ K−1 mol−1 Determine the temperature at which the reaction would be spontaneous.
Find out the value of the equilibrium constant for the following reaction at 298 K, \[\ce{2NH3_{(g)} + CO2_{(g)} ⇌ NH2CONH2_{(aq)} + H2O_{(l)}}\] Standard Gibbs energy change, `∆"G"_"r"^0` at the given temperature is –13.6 kJ mol−1.
A gas mixture of 3.67 lit of ethylene and methane on complete combustion at 25°C and at 1 atm pressure produce 6.11 lit of carbon dioxide. Find out the amount of heat evolved in kJ, during this combustion. (ΔHC(CH4)) = − 890 kJ mol−1 and (ΔHC(C2H4)) = − 1423 kJ mol−1
Solutions for 7: Thermodynamics
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Samacheer Kalvi solutions for Chemistry - Volume 1 and 2 [English] Class 11 TN Board chapter 7 - Thermodynamics
Shaalaa.com has the Tamil Nadu Board of Secondary Education Mathematics Chemistry - Volume 1 and 2 [English] Class 11 TN Board Tamil Nadu Board of Secondary Education solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Samacheer Kalvi solutions for Mathematics Chemistry - Volume 1 and 2 [English] Class 11 TN Board Tamil Nadu Board of Secondary Education 7 (Thermodynamics) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Chemistry - Volume 1 and 2 [English] Class 11 TN Board chapter 7 Thermodynamics are Thermodynamics, System and Surrounding, Zeroth Law of Thermodynamics, First Law of Thermodynamics, Enthalpy (H), Thermochemical Equations, Measurement of ΔU and ΔH Using Calorimetry, Hess’s Law of Constant Heat Summation, Lattice Energy, Various Statements of the Second Law of Thermodynamics, Second Law of Thermodynamics, Gibbs Free Energy (G), Third Law of Thermodynamics.
Using Samacheer Kalvi Chemistry - Volume 1 and 2 [English] Class 11 TN Board solutions Thermodynamics exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Samacheer Kalvi Solutions are essential questions that can be asked in the final exam. Maximum Tamil Nadu Board of Secondary Education Chemistry - Volume 1 and 2 [English] Class 11 TN Board students prefer Samacheer Kalvi Textbook Solutions to score more in exams.
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