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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Samacheer Kalvi solutions for Chemistry - Volume 1 and 2 [English] Class 11 TN Board chapter 4 - Hydrogen [Latest edition]

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Samacheer Kalvi solutions for Chemistry - Volume 1 and 2 [English] Class 11 TN Board chapter 4 - Hydrogen - Shaalaa.com
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Solutions for Chapter 4: Hydrogen

Below listed, you can find solutions for Chapter 4 of Tamil Nadu Board of Secondary Education Samacheer Kalvi for Chemistry - Volume 1 and 2 [English] Class 11 TN Board.


Evaluation
Evaluation [Pages 119 - 123]

Samacheer Kalvi solutions for Chemistry - Volume 1 and 2 [English] Class 11 TN Board 4 Hydrogen Evaluation [Pages 119 - 123]

Choose the best answer

Evaluation | Q I. 1. | Page 119

Which of the following statements about hydrogen is incorrect?

  • Hydrogen ion, \[\ce{H3O^+}\] exists freely in solution.

  • Dihydrogen acts as a reducing agent.

  • Hydrogen has three isotopes of which tritium is the most common.

  • Hydrogen never acts as cation in ionic salts.

Evaluation | Q I. 2. | Page 119

Water gas is

  • \[\ce{H2O_{(g)}}\]

  • \[\ce{CO + H2O}\]

  • \[\ce{CO + H2}\]

  • \[\ce{CO + N2}\]

Evaluation | Q I. 3. | Page 119

Which one of the following statements is incorrect with regard to ortho and para dihydrogen?

  • They are nuclear spin isomers

  • Ortho isomer has zero nuclear spin whereas the para isomer has one nuclear spin

  • The para isomer is favoured at low temperatures

  • The thermal conductivity of the para isomer is 50% greater than that of the ortho isomer.

Evaluation | Q I. 4. | Page 119

Ionic hydrides are formed by ________.

  • halogens

  • chalcogens

  • inert gases

  • group one elements

Evaluation | Q I. 5. | Page 119

Tritium nucleus contains

  • 1p + 0n

  • 2p + 1n

  • 1p + 2n

  • none of these

Evaluation | Q I. 6. | Page 119

Non-stoichiometric hydrides are formed by __________.

  • palladium, vanadium

  • carbon, nickel

  • manganese, lithium

  • nitrogen, chlorine

Evaluation | Q I. 7. | Page 120

Assertion: Permanent hardness of water is removed by treatment with washing soda.

Reason: Washing soda reacts with soluble calcium and magnesium chlorides and sulphates in hard water to form insoluble carbonates.

  • Both assertion and reason are true and reason is the correct explanation of assertion.

  • Both assertion and reason are true but reason is not the correct explanation of assertion.

  • Assertion is true but reason is false

  • Both assertion and reason are false

Evaluation | Q I. 8. | Page 120

If a body of a fish contains 1.2 g hydrogen in its total body mass, if all the hydrogen is replaced with deuterium then the increase in body weight of the fish will be

  • 1.2 g

  • 2.4 g

  • 3.6 g

  • `sqrt4.8` g

Evaluation | Q I. 9. | Page 120

The hardness of water can be determined by volumetrically using the reagent

  • sodium thiosulphate

  • potassium permanganate

  • hydrogen peroxide

  • EDTA

Evaluation | Q I. 10. | Page 120

The cause of permanent hardness of water is due to

  • Ca(HCO3)2

  • Mg(HCO3)2

  • CaCl2

  • MgCO3

Evaluation | Q I. 11. | Page 120

Zeolite used to soften hardness of water is, hydrated ___________.

  • Sodium aluminium silicate

  • Calcium aluminium silicate

  • Zinc aluminium borate

  • Lithium aluminium hydride

Evaluation | Q I. 12. | Page 120

A commercial sample of hydrogen peroxide marked as 100 volume H2O2, it means that

  • 1 ml of H2O2 will give 100 ml O2 at STP

  • 1 L of H2O2 will give 100 ml O2 at STP

  • 1 L of H2O2 will give 22.4 L O2

  • 1 ml of H2O2 will give 1 mole of O2 at STP

Evaluation | Q I. 13. | Page 121

When hydrogen peroxide is shaken with an acidified solution of potassium dichromate in presence of ether, the ethereal layer turns blue due to the formation of

  • \[\ce{Cr2O3}\]

  • \[\ce{CrO^2-_4}\]

  • \[\ce{CrO(O2)2}\]

  • none of these

Evaluation | Q I. 14. | Page 121

For decolourisation of 1 mole of acidified KMnO4, the moles of H2O2 required is

  • `1/2`

  • `3/2`

  • `5/2`

  • `7/2`

Evaluation | Q I. 15. | Page 121

Volume strength of 1.5 N H2O2 is

  • 1.5

  • 4.5

  • 16.8

  • 8.4

Evaluation | Q I. 16. | Page 121

The hybridisation of oxygen atom is H2O and H2O2 are, respectively

  • sp and sp3

  • sp and sp

  • sp and sp2

  • sp3 and sp3

Evaluation | Q I. 17. | Page 121

The reaction \[\ce{H3PO2 + D2O -> H2DPO2 + HDO}\] indicates that hypo-phosphorus acid is

  • tribasic acid

  • dibasic acid

  • monobasic acid

  • none of these

Evaluation | Q I. 18. | Page 121

In solid ice, the oxygen atom is surrounded

  • tetrahedrally by 4 hydrogen atoms

  • octahedrally by 2 oxygen and 4 hydrogen atoms

  • tetrahedrally by 2 hydrogen and 2 oxygen atoms

  • octahedrally by 6 hydrogen atoms

Evaluation | Q I. 19. | Page 121

The type of H-bonding present in ortho nitrophenol and p-nitrophenol are respectively

  • intermolecular H-bonding and intramolecular H-bonding

  • intramolecular H-bonding and intermolecular H-bonding

  • intramolecular H-bonding and no H-bonding

  • intramolecular H-bonding and intramolecular H-bonding

Evaluation | Q I. 20. | Page 122

Heavy water is used as

  • moderator in nuclear reactions

  • coolant in nuclear reactions

  • both moderator in nuclear reactions and coolant in nuclear reactions

  • none of these

Evaluation | Q I. 21. | Page 122

Water is a _________.

  • basic oxide

  • acidic oxide

  • amphoteric oxide

  • none of these

Write brief answer to the following questions

Evaluation | Q II. 1. | Page 122

Explain why hydrogen is not placed with the halogen in the periodic table.

Evaluation | Q II. 2. | Page 122

Discuss the three types of Covalent hydrides.

Evaluation | Q II. 3. | Page 122

Predict which of the following hydrides is a gas on a solid

  1. HCl
  2. NaH

Give your reason.

Evaluation | Q II. 4. | Page 122

Write the expected formulas for the hydrides of 4th-period elements. What is the trend in the formulas? In what way the first two members of the series different from the others?

Evaluation | Q II. 5. i) | Page 122

Write a chemical equation for the following reaction.

Reaction of hydrogen with tungsten (VI) oxide on heating.

Evaluation | Q II. 5. ii) | Page 122

Write a chemical equation for the following reaction.

Hydrogen gas and chlorine gas.

Evaluation | Q II. 6. i) | Page 122

Complete the following chemical reaction and classify the reaction.

\[\ce{KMnO4 + H2O2 ->}\]

  • Hydrolysis reaction

  • Redox reaction

  • Hydration reaction

Evaluation | Q II. 6. ii) | Page 122

Complete the following chemical reaction and classify the reaction.

\[\ce{CrCl3 + H2O ->}\]

  • Hydrolysis reaction

  • Redox reaction

  • Hydration reaction

Evaluation | Q II. 6. iii) | Page 122

Complete the following chemical reaction and classify the reaction.

\[\ce{CaO + H2O ->}\]

  • Hydrolysis reaction

  • Redox reaction

  • Hydration reaction

Evaluation | Q II. 7. | Page 122

Hydrogen peroxide can function as an oxidising agent as well as the reducing agent. substantiate this statement with suitable examples.

Evaluation | Q II. 8. | Page 123

Do you think that heavy water can be used for drinking purposes?

Evaluation | Q II. 9. | Page 123

What is a water-gas shift reaction?

Evaluation | Q II. 10. | Page 123

Justify the position of hydrogen in the periodic table?

Evaluation | Q II. 11. a. | Page 123

What are isotopes?

Evaluation | Q II. 11. b. | Page 123

Write the names of isotopes of hydrogen.

Evaluation | Q II. 12. | Page 123

Give the uses of heavy water.

Evaluation | Q II. 13. | Page 123

Explain the exchange reactions of deuterium.

Evaluation | Q II. 14. | Page 123

How do you convert para-hydrogen into ortho hydrogen?

Evaluation | Q II. 15. | Page 123

Mention the uses of deuterium.

Evaluation | Q II. 16. | Page 123

Explain the preparation of hydrogen using electrolysis.

Evaluation | Q II. 17. | Page 123

A group-1 metal (A) which is present in common salt reacts with (B) to give compound (C) in which hydrogen is present in –1 oxidation state. (B) on reaction with a gas (C) to give universal solvent (D). The compound (D) on reacts with (A) to give (E), a strong base. Identify A, B, C, D and E. Explain the reactions.

Evaluation | Q II. 18. | Page 123

An isotope of hydrogen (A) reacts with diatomic molecule of element which occupies group number 16 and period number 2 to give compound (B) is used as a moderator in nuclear reaction. (A) adds on to a compound (C), which has the molecular formula C3H6 to give (D). Identify A, B, C and D.

Evaluation | Q II. 19. | Page 123

NH3 has an exceptionally high melting point and boiling point as compared to those of the hydrides of the remaining element of group 15 - Explain.

Evaluation | Q II. 20. | Page 123

Why interstitial hydrides have a lower density than the parent metal?

Evaluation | Q II. 21. | Page 123

How do you expect the metallic hydrides to be useful for hydrogen storage?

Evaluation | Q II. 22. | Page 123

Arrange NH3, H2O and HF in the order of increasing magnitude of hydrogen bonding and explain the basis for your arrangement.

Evaluation | Q II. 23. | Page 123

Compare the structures of H2O and H2O2.

Solutions for 4: Hydrogen

Evaluation
Samacheer Kalvi solutions for Chemistry - Volume 1 and 2 [English] Class 11 TN Board chapter 4 - Hydrogen - Shaalaa.com

Samacheer Kalvi solutions for Chemistry - Volume 1 and 2 [English] Class 11 TN Board chapter 4 - Hydrogen

Shaalaa.com has the Tamil Nadu Board of Secondary Education Mathematics Chemistry - Volume 1 and 2 [English] Class 11 TN Board Tamil Nadu Board of Secondary Education solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Samacheer Kalvi solutions for Mathematics Chemistry - Volume 1 and 2 [English] Class 11 TN Board Tamil Nadu Board of Secondary Education 4 (Hydrogen) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

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Concepts covered in Chemistry - Volume 1 and 2 [English] Class 11 TN Board chapter 4 Hydrogen are Hydrogen, Preparation of Hydrogen Peroxide, Properties of Hydrogen, Uses of Hydrogen Peroxide, Compounds of Hydrogen, Heavy Water, Hydrogen Peroxide, Hydrides, Hydrogen Bonding - Introduction.

Using Samacheer Kalvi Chemistry - Volume 1 and 2 [English] Class 11 TN Board solutions Hydrogen exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Samacheer Kalvi Solutions are essential questions that can be asked in the final exam. Maximum Tamil Nadu Board of Secondary Education Chemistry - Volume 1 and 2 [English] Class 11 TN Board students prefer Samacheer Kalvi Textbook Solutions to score more in exams.

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