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Explain the exchange reactions of deuterium. - Chemistry

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प्रश्न

Explain the exchange reactions of deuterium.

संक्षेप में उत्तर

उत्तर

When compounds containing hydrogen are treated with D2O, hydrogen undergoes an exchange for deuterium. This reaction is known as the exchange reaction of deuterium.

\[\ce{2NaOH + D2O -> 2NaOD + HOD}\]

\[\ce{HCl + D2O -> DCl + HOD}\]

\[\ce{NH4Cl + 4D2O -> ND4Cl + 4HOD}\]

These exchange reactions are useful in determining the number of ionic hydrogens present in a given compound. For example, when D2O is treated with hypo-phosphorus acid only one hydrogen atom is exchanged with deuterium. It indicates that it is a monobasic acid.

\[\ce{H3PO2 + D2O -> H2DPO2 + HDO}\]

It is also used to prepare some deuterium compounds:

\[\ce{Al4C3 + 12D2O -> 4Al(OD)3 + 3CD4}\]

\[\ce{CaC2 + 2D2O -> Ca(OD)2 + C2D2}\]

\[\ce{Mg3N2 + 6D2O -> 3Mg(OD)2 + 2ND3}\]

\[\ce{Ca3P2 + 6D2O -> 3Ca(OD)2 + 2PD3}\]

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Properties of Hydrogen
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अध्याय 4: Hydrogen - Evaluation [पृष्ठ १२३]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 4 Hydrogen
Evaluation | Q II. 13. | पृष्ठ १२३
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