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प्रश्न
1 mole of an ideal gas, maintained at 4.1 atm and at a certain temperature, absorbs heat 3710 J and expands to 2 litres. Calculate the entropy change in the expansion process.
उत्तर
Given, n = 1 mole
P = 4.1 atm
V = 2 Lit
T = ?
q = 3710 J
∆S = `"q"/"T"`
∆S = `"q"/(("PV"/"nR"))`
∆S = `"nRq"/"PV"`
∆S = `(1 xx 0.082 "lit atm K"^-1 xx 3710 "J")/(4.1 "atm" xx 2 "lit")`
∆S = 37.10 JK−1
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