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Calculate the entropy change in the system, and surroundings, and the total entropy change in the universe during a process in which 245 J - Chemistry

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प्रश्न

Calculate the entropy change in the system, and surroundings, and the total entropy change in the universe during a process in which 245 J of heat flows out of the system at 77°C to the surrounding at 33°C.

संख्यात्मक

उत्तर

Given, Tsys = 77°C = (77 + 273) = 350 K

Tsurr = 33°C = (33 + 273) = 360 K

q = 245 J

∆Ssys = `"q"/"T"_"sys" = (−245)/350` = − 0.7 JK−1

∆Ssurr = `"q"/"T"_"sys" = (+245)/306` = + 0.8 JK−1

∆Suniv = ∆Ssys + ∆Ssurr

∆Suniv = − 0.7 JK−1 + 0.8 JK−1

∆Suniv = 0.1 JK−1

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Various Statements of the Second Law of Thermodynamics
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Thermodynamics - Evaluation [पृष्ठ २२५]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 7 Thermodynamics
Evaluation | Q II. 30. | पृष्ठ २२५
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