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Derive the relation between ∆H and ∆U for an ideal gas. Explain each term involved in the equation. - Chemistry

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प्रश्न

Derive the relation between ∆H and ∆U for an ideal gas. Explain each term involved in the equation.

संख्यात्मक

उत्तर

When the system at constant pressure undergoes changes from an initial state with H1, U1, V1 and P parameters to a final state with H2, U2, V2 and P parameters, the change in enthalpy ∆H, is given by

H = U + PV

At initial state H1 = U1 + PV1    ...(1)

At final state H2 = U2 + PV2    ...(2)

change in enthalpy is (2) – (1)

⇒ (H2 – H1) = (U2 – U1) + P(V2 – V1)

∆H = ∆U + P∆V     ...(3)

As per first law of thermodynamics,

∆U = q + w; w = - P∆V 

Equation (3) becomes

∆H = q + w + P∆V

∆H = qp – P∆V + P∆V

∆H = qp    ...(4)

qp is the heat absorbed at constant pressure and is considered as heat content.

Consider a closed system of gases which are chemically reacting to form gaseous products at constant temperature and pressure with Vi and Vf, as the total volumes of the reactant and product gases respectively, and ni and nf as the number of moles of gaseous reactants and products, then,

For reactants: P Vi = ni RT   ...(5)

For products: P Vf = nf RT   ...(6)

(6) - (5)

P (Vf – Vi) = (nf – ni) RT

P∆V = ∆ng RT   ...(7)

Substituting in (7) in (3)

∆H = ∆U + P∆V

∆H = ∆U + ∆ng RT 

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Enthalpy (H)
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Thermodynamics - Evaluation [पृष्ठ २२५]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 7 Thermodynamics
Evaluation | Q II. 25. | पृष्ठ २२५
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