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प्रश्न
What is the kinetic energy of an electron in electron volts with mass equal to double its rest mass?
उत्तर
If m0 is the rest mass of an electron and c is the speed of light, then kinetic energy (E) of the electron = mc2 − m0c2. ...........(1)
According to the question,
m = 2m0
E = (2m0 − m0)c2
E= m0c2 = 9.1 × 10−31 × 9 × 1016 J
\[E = \frac{9 . 1 \times 9}{1 . 6} \times \frac{{10}^{- 15}}{{10}^{- 19}} = 51 . 18 \times {10}^4 eV = 511\text{ keV}\]
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