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प्रश्न
What mass of hydrogen peroxide will be present in 2 litres of a 5 molar solution? Calculate the mass of oxygen which will be liberated by the decomposition of 200 mL of this solution.
उत्तर
Molecular mass of \[\ce{H2O2}\] = 34
Mass of \[\ce{H2O2}\] present in 1 molar solution = 34 g
Mass of \[\ce{H2O2}\] present in 2 litres of 1 molar solution = 2 × 34 = 68 g
Mass of \[\ce{H2O2}\] present in 200 mL solution of 1 molar \[\ce{H2O2}\] solution = `34/5`
= \[\ce{6.8 g 2\underset{\underset{6.8 g}{68 g}}{H2}O2 -> 2H2O + \underset{\underset{3.2 g}{32 g}}{O2}}\]
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संबंधित प्रश्न
Why does \[\ce{H+}\] ion always get associated with other atoms or molecules?
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(iv) Heavy water has lower boiling point than ordinary water.
How is heavy water prepared? Compare its physical properties with those of ordinary water.
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[Given that molar mass of H = 1 g mol−1 and O = 16 g mol−1)
