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Question
What mass of hydrogen peroxide will be present in 2 litres of a 5 molar solution? Calculate the mass of oxygen which will be liberated by the decomposition of 200 mL of this solution.
Solution
Molecular mass of \[\ce{H2O2}\] = 34
Mass of \[\ce{H2O2}\] present in 1 molar solution = 34 g
Mass of \[\ce{H2O2}\] present in 2 litres of 1 molar solution = 2 × 34 = 68 g
Mass of \[\ce{H2O2}\] present in 200 mL solution of 1 molar \[\ce{H2O2}\] solution = `34/5`
= \[\ce{6.8 g 2\underset{\underset{6.8 g}{68 g}}{H2}O2 -> 2H2O + \underset{\underset{3.2 g}{32 g}}{O2}}\]
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