Question

The volume of '10 Vol' of H₂O₂ required to liberate 500 mL O₂ at NTP is ______.

Options

• 50 mL

• 25 mL

• 100 mL

• 125 mL

Answer 1

The volume of '10 Vol' of H₂O₂ required to liberate 500 mL O₂ at NTP is 50 mL.

Explanation:

$$\underset{1\mathrm{ml}}{\underset{1\mathrm{L}}{\mathrm{H}{\phantom{A}}_2\mathrm{O}{\phantom{A}}_2}}⟶\mathrm{H}{\phantom{A}}_2\mathrm{O}+\frac{1}{2}\mathrm{O}{\phantom{A}}_2\underset{10\mathrm{ml}}{\underset{10\mathrm{L}}{(\mathrm{g})}}$$

∴ 500 ml O₂ → ${\displaystyle \frac{1}{10}\times 500}$ = 50 ml H₂O₂.