Question

The volume of '10 Vol' of H₂O₂ required to liberate 500 mL O₂ at NTP is ______.

पर्याय

• 50 mL

• 25 mL

• 100 mL

• 125 mL

Answer 1

The volume of '10 Vol' of H₂O₂ required to liberate 500 mL O₂ at NTP is 50 mL.

Explanation:

\[\ce{\underset{1 ml}{\underset{1 L}{H2O2}} -> H2O + 1/2 O2 \underset{10 ml}{\underset{10 L}{(g)}}}\]

∴ 500 ml O₂ → `1/10 xx 500` = 50 ml H₂O₂.