Advertisements
Advertisements
Question
Why does \[\ce{H+}\] ion always get associated with other atoms or molecules?
Options
Ionisation enthalpy of hydrogen resembles that of alkali metals.
Its reactivity is similar to halogens.
It resembles both alkali metals and halogens.
Loss of an electron from hydrogen atom results in a nucleus of very small size as compared to other atoms or ions. Due to smal size it cannot exist free.
Solution
Loss of an electron from hydrogen atom results in a nucleus of very small size as compared to other atoms or ions. Due to smal size it cannot exist free.
Explanation:
Loss of the electron from hydrogen atom results in nucleus size \[\ce{(H+)}\] of 1.5 × 10–3. This is extremely small as compared to normal atomic and ionic sizes of 50 to 200 pm. As a consequence, \[\ce{H+}\] does not exist freely and is always associated with other atoms or molecules.
APPEARS IN
RELATED QUESTIONS
A commercial sample of hydrogen peroxide marked as 100 volume H2O2, it means that
Volume strength of 1.5 N H2O2 is
Which of the following statement(s) is/are correct in the case of heavy water?
(i) Heavy water is used as a moderator in nuclear reactor.
(ii) Heavy water is more effective as solvent than ordinary water.
(iii) Heavy water is more associated than ordinary water.
(iv) Heavy water has lower boiling point than ordinary water.
How is heavy water prepared? Compare its physical properties with those of ordinary water.
Give a method for the manufacture of hydrogen peroxide and explain the reactions involved therein.
What mass of hydrogen peroxide will be present in 2 litres of a 5 molar solution? Calculate the mass of oxygen which will be liberated by the decomposition of 200 mL of this solution.
Hydrogen peroxide is obtained by the electrolysis of ______.
Which of the following will happen when a little hydrogen peroxide is added to a solution of ferrous sulphate?
Hydrogen peroxide for the first time was prepared by:
In a basic medium, H2O2 exhibits which of the following reactions?
(A) \[\ce{Mn^{2+} -> Mn^{4+}}\]
(B) \[\ce{I2 -> I^-}\]
(C) \[\ce{PbS -> PbSO4}\]
Choose the most appropriate answer from the options given below.
