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प्रश्न
What must be added to 2a3 + 5a – a2 – 6 to get a2 – a – a3 + 1?
योग
उत्तर
We get, the required result by subtracting
2a3 + 5a – a2 – 6 from - a3 + a2 - a + 1
= (- a3 + a2 - a + 1) - (2a3 – a2 + 5a – 6)
= - a3 + a2 - a + 1 - 2a3 + a2 - 5a + 6
= - a3 - 2a3 + a2 + a2 - a - 5a + 1 + 6
= - 3a3 + 2a2 - 6a + 7
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