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By How Much Does 8x3 – 6x2 + 9x – 10 Exceed 4x3 + 2x2 + 7x -3 ? - Mathematics

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प्रश्न

By how much does 8x3 – 6x2 + 9x – 10 exceed 4x3 + 2x2 + 7x -3? 

योग

उत्तर

8x3 – 6x2 + 9x – 10 exceeds 4x3 + 2x2 + 7x -3

= (8x3 - 6x2 + 9x - 10) - (4x3 + 2x2 + 7x - 3)

= 8x3 - 6x2 + 9x - 10 - 4x3 + 2x2 + 7x - 3

= 8x3 - 4x3 - 6x2 - 2x2 + 9x - 7x - 10 + 3

= 4x3 - 8x2 + 2x - 7 

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Performs Operations (Addition and Subtraction) on Algebraic Expressions with Integral Coefficients Only.
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अध्याय 11: Fundamental Concepts (Including Fundamental Operations) - Exercise 11 (B)

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सेलिना Concise Mathematics [English] Class 7 ICSE
अध्याय 11 Fundamental Concepts (Including Fundamental Operations)
Exercise 11 (B) | Q 12
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