Advertisements
Advertisements
प्रश्न
By how much does 8x3 – 6x2 + 9x – 10 exceed 4x3 + 2x2 + 7x -3?
उत्तर
8x3 – 6x2 + 9x – 10 exceeds 4x3 + 2x2 + 7x -3
= (8x3 - 6x2 + 9x - 10) - (4x3 + 2x2 + 7x - 3)
= 8x3 - 6x2 + 9x - 10 - 4x3 + 2x2 + 7x - 3
= 8x3 - 4x3 - 6x2 - 2x2 + 9x - 7x - 10 + 3
= 4x3 - 8x2 + 2x - 7
APPEARS IN
संबंधित प्रश्न
The perimeter of a triangle is 14a2 + 20a + 13. Two of its sides are 3a2 + 5a + 1 and a2 + 10a – 6. Find its third side.
Simplify: x - (x - y) - y - (y - x)
Simplify: 4(3x - 8) - 3(5x + 3) - 2(6x - 8)
Copy and complete the following multi-plication:
3a + 2b
× - 3xy
Copy and complete the following multi-plication:
2a - b + 3c
× 2a - 4b
Multiply: x2 + 5yx - 3y2 and 2x2y
Simplify: `"6k"/7 - ("8k"/9 - "k"/3)`
Simplify: `"x"/5 + "x + 1"/2`
Simplify: `(2"p" + "p"/7) div ("9p"/10 + "4p")`
Simplify: `("5k"/8 - "3k"/5) div "k"/4`