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When 2x3 – 9x2 + 10x – p is divided by (x + 1), the remainder is – 24.Find the value of p. - Mathematics

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प्रश्न

When 2x3 – 9x2 + 10x – p is divided by (x + 1), the remainder is – 24.Find the value of p.

योग

उत्तर

Let x + 1 = 0 then x = -1
Substituting the value of x in f(x)
f(x) = 2x3 – 9x2 + 10x – p
f(–1) = 2(–1)3 – 9(–1)2 + 10(–1) – p
= –2 – 9 – 10 – p
= –21 – p
∵ the remainder = –24
∴ –21 – p = –24
⇒ p = –24 + 21
= –3
∴ p = 3.

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अध्याय 6: Factorization - Chapter Test

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