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प्रश्न
When propanamide is treated with bromine and alcoholic NaOH, it gives ______.
विकल्प
Propan-2-amine
Ethanamine
Propan-1-amine
Methanamine
MCQ
रिक्त स्थान भरें
उत्तर
When propanamide is treated with bromine and alcoholic NaOH, it gives Ethanamine.
Explanation:
\[\ce{\underset{\text{Propanamide}}{C2H5CONH2} + Br2 + 4NaOH -> \underset{\text{Ethanamine}}{C2H5NH2} + 2H2O + Na2CO3 + 2NaBr}\]
Hoffmann bromamide reaction: 1° amine with one carbon less is formed.
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