Question

When propanamide is treated with bromine and alcoholic NaOH, it gives ______.

Options

• Propan-2-amine

• Ethanamine

• Propan-1-amine

• Methanamine

Answer 1

When propanamide is treated with bromine and alcoholic NaOH, it gives Ethanamine.

Explanation:

\[\ce{\underset{\text{Propanamide}}{C2H5CONH2} + Br2 + 4NaOH -> \underset{\text{Ethanamine}}{C2H5NH2} + 2H2O + Na2CO3 + 2NaBr}\]

Hoffmann bromamide reaction: 1° amine with one carbon less is formed.