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प्रश्न
When the displacement of a simple harmonic oscillator is half of its amplitude, its P.E. is 3 J. Its total energy is ______
विकल्प
6 J
12 J
15 J
20 J
उत्तर
When the displacement of a simple harmonic oscillator is half of its amplitude, its P.E. is 3 J. Its total energy is 12 J.
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संबंधित प्रश्न
Deduce the expressions for the kinetic energy and potential energy of a particle executing S.H.M. Hence obtain the expression for the total energy of a particle performing S.H.M and show that the total energy is conserved. State the factors on which total energy depends.
At what distance from the mean position is the speed of a particle performing S.H.M. half its maximum speed. Given the path length of S.H.M. = 10 cm.
Deduce the expression for kinetic energy, potential energy, and total energy of a particle performing S.H.M. State the factors on which total energy depends.
The quantity which does not vary periodically for a particle performing SHM is ______.
The frequency of oscillation of a particle of mass m suspended at the end of a vertical spring having a spring constant k is directly proportional to ____________.
The kinetic energy of a particle, executing SHM is 16 J, when it is in its mean position. If the amplitude of oscillation is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation is ____________.
A body executing SHM has amplitude of 4 cm. What is the distance at which the body has equal value of both K.E. and P.E.?
The displacement of a particle performing S.H.M. is given by x = 10 sin (`omega"t"+ alpha`) metre. If the displacement of the particle is 5 m, then the phase of S.H.M. is ____________.
The ratio of kinetic energy to the potential energy of a particle executing S.H.M. at a distance equal to (1/3)rd of its amplitude is ______.
The kinetic energy of a particle performing S.H.M. is `1/n` times its potential energy. If the amplitude of S.H.M. is 'A', then the displacement of the particle will be ______
A body oscillates simply harmonically with a period of 2 seconds, starting from the origin. Its kinetic energy will be 75% of the total energy after time ______
`(sin30^circ = cos60^circ = 1/2)`
A particle starting from the mean position performs linear S.H.M. Its amplitude is 'A' and total energy is 'E'. At what displacement its kinetic energy is 3E/4?
If the length of an oscillating simple pendulum is made `1/3` times at a place keeping amplitude the same, then its total energy (E) will be ______
The total energy of a particle performing S.H.M. is 'NOT' proportional to ______
A particle starts from mean position and performs S.H.M. with period 6 second. At what time its kinetic energy is 50% of total energy?
`(cos45^circ=1/sqrt2)`
A particle performs S.H.M. Its potential energies are 'U1' and 'U2' at displacements 'x1' and 'x2' respectively. At displacement (x1 + x2), its potential energy 'U' is ______.
A particle performs S.H.M. of period 24 s. Three second after passing through the mean position it acquires a velocity of 2 π m/s. Its path length is ______.
`(sin45^circ=cos45^circ=1/sqrt2)`
A particle starts oscillating simple harmonically from its equilibrium position with time period T. At time t = T/12, the ratio of its kinetic energy to potential energy is ______.
`[sin pi/3 = cos pi/6 = sqrt3/2, sin pi/6 = cos pi/3 = 1/2]`
A simple harmonic oscillator has amplitude A, angular velocity ω and mass m. Then, average energy in one time period will be ______.
A particle executes SHM with an amplitude of 10 cm and frequency 2 Hz. At t = 0, the particle is at a point, where potential energy and kinetic energy are same. The equation of displacement of particle is ______.
