English

When the displacement of a simple harmonic oscillator is half of its amplitude, its P.E. is 3 J. Its total energy is ______ - Physics

Advertisements
Advertisements

Question

When the displacement of a simple harmonic oscillator is half of its amplitude, its P.E. is 3 J. Its total energy is ______ 

Options

  • 6 J

  • 12 J

  • 15 J

  • 20 J

MCQ
Fill in the Blanks

Solution

When the displacement of a simple harmonic oscillator is half of its amplitude, its P.E. is 3 J. Its total energy is 12 J.

shaalaa.com
The Energy of a Particle Performing S.H.M.
  Is there an error in this question or solution?
Chapter 5: Oscillations - MCQ’s

APPEARS IN

SCERT Maharashtra Physics [English] 12 Standard HSC
Chapter 5 Oscillations
MCQ’s | Q 6

RELATED QUESTIONS

The total energy of a body of mass 2 kg performing S.H.M. is 40 J. Find its speed while crossing the center of the path.


Deduce the expressions for the kinetic energy and potential energy of a particle executing S.H.M. Hence obtain the expression for the total energy of a particle performing S.H.M and show that the total energy is conserved. State the factors on which total energy depends.


Deduce the expression for kinetic energy, potential energy, and total energy of a particle performing S.H.M. State the factors on which total energy depends. 


The quantity which does not vary periodically for a particle performing SHM is ______.


The frequency of oscillation of a particle of mass m suspended at the end of a vertical spring having a spring constant k is directly proportional to ____________.


The kinetic energy of a particle, executing SHM is 16 J, when it is in its mean position. If the amplitude of oscillation is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation is ____________.


A body executing SHM has amplitude of 4 cm. What is the distance at which the body has equal value of both K.E. and P.E.?


The displacement of a particle performing S.H.M. is given by x = 10 sin (`omega"t"+ alpha`) metre. If the displacement of the particle is 5 m, then the phase of S.H.M. is ____________.


The total energy of a simple harmonic oscillator is proportional to ______.


The ratio of kinetic energy to the potential energy of a particle executing S.H.M. at a distance equal to (1/3)rd of its amplitude is ______.


The kinetic energy of a particle performing S.H.M. is `1/n` times its potential energy. If the amplitude of S.H.M. is 'A', then the displacement of the particle will be ______ 


A body oscillates simply harmonically with a period of 2 seconds, starting from the origin. Its kinetic energy will be 75% of the total energy after time ______

`(sin30^circ = cos60^circ = 1/2)`


A particle starting from the mean position performs linear S.H.M. Its amplitude is 'A' and total energy is 'E'. At what displacement its kinetic energy is 3E/4?


A simple pendulum of length 'L' has mass 'm' and it oscillates freely with amplitude 'A'. At the extreme position, its potential energy is ______ 

(g = acceleration due to gravity)


The total energy of a particle performing S.H.M. is 'NOT' proportional to ______ 


The potential energy of a particle executing S.H.M is 2.5 J, when its displacement is half of amplitude. The total energy of the particle is ______.


Two springs of spring constants 'K' and '2K' are stretched by same force. If 'E1' and 'E2' are the potential energies stored in them respectively, then ______.


A particle starts from mean position and performs S.H.M. with period 6 second. At what time its kinetic energy is 50% of total energy?

`(cos45^circ=1/sqrt2)`


A particle performs S.H.M. of period 24 s. Three second after passing through the mean position it acquires a velocity of 2 π m/s. Its path length is ______.

`(sin45^circ=cos45^circ=1/sqrt2)`


A particle starts oscillating simple harmonically from its equilibrium position with time period T. At time t = T/12, the ratio of its kinetic energy to potential energy is ______.

`[sin  pi/3 = cos  pi/6 = sqrt3/2, sin  pi/6 = cos  pi/3 = 1/2]`


A simple harmonic oscillator has amplitude A, angular velocity ω and mass m. Then, average energy in one time period will be ______.


A body of mass 0.5 kg performs SHM with amplitude 3 cm and force constant 10 N/m. Find its total energy.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×