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प्रश्न
Which term of A.P. 5, 15, 25 ………… will be 130 more than its 31st term?
उत्तर
The given A.P is 5, 15, 25,...
Here, a = 5 and d = 15 - 5 = 10
Now `t_31 = a + 30d = 5 + 30 xx 10 = 5 + 300 = 305`
Let the required term be nth term.
`∴ t_n - t_31 = 130`
`=> [a + (n - 1)d] - 305 = 130`
=> 5 + (n - 1)(10) = 435
=> n - 1 = 43
=> n = 44
Thus reuired term = 44th term.
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