Question

The 7^th term of the given Arithmetic Progression (A.P.):

${\displaystyle \frac{1}{a},(\frac{1}{a}+1),(\frac{1}{a}+2)}$... is:

विकल्प

• ${\displaystyle (\frac{1}{a}+6)}$

• ${\displaystyle (\frac{1}{a}+7)}$

• ${\displaystyle (\frac{1}{a}+8)}$

• ${\displaystyle (\frac{1}{a}+7^7)}$

Answer 1

${\displaystyle (\frac{1}{a}+6)}$

Explanation:

Given A.P. is ${\displaystyle \frac{1}{a},(\frac{1}{a}+1),(\frac{1}{a}+2)}$

Here, first term, A = ${\displaystyle \frac{1}{a}}$

Common difference D = ${\displaystyle \frac{1}{a}+1-\frac{1}{a}}$ = 1

Then, 7^th term of A.P. = A + (n – 1)D

= ${\displaystyle \frac{1}{a}+(7-1)\times 1}$

= ${\displaystyle \frac{1}{a}+6}$