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Question
The 7th term of the given Arithmetic Progression (A.P.):
`1/a, (1/a + 1), (1/a + 2)`... is:
Options
`(1/a + 6)`
`(1/a + 7)`
`(1/a + 8)`
`(1/a + 7^7)`
Solution
`bb((1/a + 6))`
Explanation:
Given A.P. is `1/a, (1/a + 1), (1/a + 2)`
Here, first term, A = `1/a`
Common difference D = `1/a + 1 - 1/a` = 1
Then, 7th term of A.P. = A + (n – 1)D
= `1/a + (7 - 1) xx 1`
= `1/a + 6`
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