Advertisements
Advertisements
प्रश्न
Why carbohydrates are generally optically active?
उत्तर
Carbohydrates are generally optically active because they have one or more chiral carbon atoms in their molecules. For example, Glucose has four chiral carbons and therefore it is optically active.
\[\begin{array}{cc}
\ce{CHO}\\
|\phantom{....}\\
\ce{^*CHOH}\\
|\phantom{....}\\
\ce{^*CHOH}\\
|\phantom{....}\\
\ce{^*CHOH}\\
|\phantom{....}\\
\ce{^*CHOH}\\
|\phantom{....}\\
\phantom{...}\ce{CH2OH}
\end{array}\]
\[\ce{^*C}\] - Chiral carbon
APPEARS IN
संबंधित प्रश्न
Write a chemical reaction to convert glucose into glucose cyanohydrin.
Which of the following monosaccharides is a tetrose sugar?
______ is the prosthetic group of glycoproteins.
Monosaccharides are ______ in nature.
Raffinose, sucrose and stachyose are respectively ____________.
Which element among the following is not present in saccharine?
Complete hydrolysis of cellulose gives ____________.
The glycosidic linkage present in maltose is ______.
Why carbohydrates are generally optically active?
Why carbohydrates are generally optically active.